Answers on String Manipulation

[Guest rkruijer]

Do you recognize this list? Looking in our forum I have noticed that any questions on the subject of string manipulation will get very little response if any. With this tutorial I will try to put an end to that. Took me some time to sort it out and I will share it with you today.The examples below can be reconstructed and/or combined. I will give you only the essentials!lc Converts a string to lowercase.uc Converts a string to uppercase.cap Capitalizes a string.chr Converts a number to a symbol.ord Converts a symbol to an integer.scat Concatenates strings.schr Finds a symbol in a string.scmp Compares strings.scmi Compares strings, ignoring case.sstr Finds a substring.ssub Extracts a substring.symb Extracts a single character.slen Will return the length of a stringThe ord instruction converts a symbol also called character into it's ascii code (integer) The chr instruction converts an ascii code (integer) into a character or symbol if you like. They are the same. - slen - Example 1. Length of the designation string '01L-19R' Will return 7 (@c:WaypointAirportRunwayDesignation) slen (>;L:Rqylength, number) - scmp - Example 2. Compare strings. If equal will return -1 With the '!' added it will return 1 so if{} can be used. (@c:NearestAirportCurrentIdent,string) 'EHAM' scmp ! (>L:Var5, bool) - scmp - Example 2a. Compare strings. Test String for Airport ICAO. 0 (>L:TransitionLevel,enum) c (@c:NearestAirportCurrentIdent,string) sp0l0 'EHAM' scmp ! if{ 40 } l0 'EGLL' scmp ! if{ 70 }(>L:TransitionLevel,enum) - sstr - Example 3. Find a substring. Test ICAO string for Country.(@c:NearestAirportCurrentIdent,string) sp0 l0 'EH' sstr ! if{ 3000 } l0 'EG' sstr ! if{ 6000 } l0 'ED' sstr ! if{ 5000 } (>L:Inflight_TA,number) - schr - Example 4. Find a character in a string. Will return the position of the symbol starting with 0 in the string '01L-19R' 'L' L:found will return 2 'R' will return 6(@c:WaypointAirportRunwayDesignation) 'L' ord schr (>L:Lfound,number) (@c:WaypointAirportRunwayDesignation) 'R' ord schr (>L:Rfound,number) - ssub - Example 5. Extract part of a string. From '01L-19R' '01L' will be extracted. The result cannot be entered into a variable but it can be printed!Notice the 0 3. 0 is the starting point and 3 the length%Deel1 %((@c:WaypointAirportRunwayDesignation) 0 3 ssub)%!s!- ssub - Example 5a. Extract part of a string. From 'Amsterdam' 'ster' will be printed.Notice that here only one pare of brackets must be used! %Substr %( 'Amsterdam' 2 4 ssub )%!s! - uc - Example 6. Output in uppercase From 'Amsterdam' 'ster' will be converted to 'STER'%Substr %( 'Amsterdam' 2 4 ssub uc)%!s! - cap - Example 7. First symbol will be converted to capital. From 'Amsterdam' 'ster' will converted to 'Ster' %Substr %( 'Amsterdam' 2 4 ssub cap)%!s! - symb - Example 8. Extract one character. From '01L-19R' 'L' will be printed.Notice that only the pointer 2 is required. %((@c:WaypointAirportRunwayDesignation) 2 symb)%!s - symb - Example 8a. Extract one character. From 'Amsterdam' 'A' will be printed.%( 'Amsterdam' 0 symb )%!s! - scat - Example 9. Concattenation. Given: L:Var1=49 L:Var2=53 L:Var2=53 'KLM153' (my callsign) will be printed.Notice that the respective ascii codes are first converted to a symbol/character and then added.%( 'KLM' (L:Var1,enum) chr scat (L:Var2,enum) chr scat (L:Var3,enum) chr scat )%!s! - lc - Example 10. Another example? I've done my share. I will leave this lowercase instruction to you!Roelof Kruijer

[Guest ridgell]

great post ! thxa copy and paste for my fs9 bible

[Guest iagman]

Roelof,Thanks for taking the time to share this information. Teaching by example is my kind of cake.Glenn

[Guest rkruijer]

Thank you Gentleman for appriciating this effort.A better readable and slightly changed Word document can be found at my site: http://members.home.nl/rkruijer/ Go to the English Page! You will find the link at the top!Roelof