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Flap Retraction and Bank Angle limits on Take-off

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Hello again :-) I know the flap speeds are V-ref 20, 40, 60, 80 but lets say I depart with flaps 5; can I bring the flaps to 1 at V-ref 20 then up on V-ref 40? Or I have to wait until V-ref 60 or V-ref 80 to retract the flaps? Also I am flying a SID with a left turn immediately after departure, what is the bank angle limit on take-off and how high should I fly before starting any turn on the 767? Thank You.

Bring flaps to one passing Vref+40, and to up passing Vref+60.The minimum manouvre speeds will provide a 1.3G buffet margin, which equates to 40 degree bank before stall onset. This allows for 25 degrees normal bank angle, with an overshoot of 15 degrees.For all phases of flight the maximum bank angle is 25 degrees, this includes immediately after takeoff, even if you've suffered an engine failure.

>Bring flaps to one passing Vref+40, and to up passing >Vref+60. Hi HPSOV thanks for the reply. So if I can retract the flaps at Vref+60 without overbank protection to 40 degrees ofcourse at what bank angle will the airplane then stall? Also does this apply during the approach? For example would this be right on the approach, Vref+60=Flaps 1 Vref+40=Flaps 5 Vref+20=Flaps 15/20Vref =Flaps 30 Thank You :-)

november678x,Remember that you are only allowed to retract the flaps 20 knots before the min flap manoeuvre speed if you are accelerating, as on a take-off departure.In the case of an approach, where your speed is steady-state or decelerating, the appropriate flap must be selected prior to decelerating below the min manouevre speed.For example, on departure, you can select flaps up at Vref+60 if you are accelerating toward Vref+80 (flaps up min manouevre speed)or beyond. On approach, you cannot go slower that Vref+80 without selecting FLAP 1.With respect to your question on stall speeds, you can calculate the stall speed based on the following forumula (stall speed is proportional to the square of the g loading)a. g loading for a level turn = 1 / COS(bank angle) For example, at 45 deg of bank = 1 / .707 = 1.41gb. percent increase in stall speed over a 1 g stall is SQRT(g)So for 45 deg bank, stall speed is SQRT(1.41) x the 1 g stall speed or approx 120 % in this case. So if the 1 g stall speed for that weight was 100 knots, the stall speed at 45 deg of bank would be 120 knots.Hope this helps clarify the situation for you.Kevin in CYOW

Yes thank you :-) but just to make sure there is still protection at -20 knots bellow min flap maneuver speed. If I retract the flaps -20 knots before the min flap maneuver speed for flaps 5, 1 and 0 can I still make the 25-degree bank turn? Can I still get to 30 degree at least without risk of stalling? Or do I have to accelerate to the min flap maneuver speed before beginning any turn. Thank You

november678xYes, you can still make the turn (as long as you are accelerating toward the next flap speed) and you will not be near stalling at 30 deg of bank.Kevin in CYOW

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