Hello simmers

 

 

 I have PFPX using it with the REX with REX weather engine (to online weather).

 

 I need to know the degree of the HEAD WIND (nose wind direction).

 

-Does the PFPX giving the HEAD WIND in the information of the flight route automatically, or the REX weather engine provide it ?

 

- i need to know it to put the it in the FMC takeoff page importantly ?

 

 

Thx.

Tune in ATIS or hit shift Z.

Tune in ATIS or hit shift Z.

Be more detailed BIGSKY !

Shift Z  - that's what the man said.  

Go into your FSX.cfg and alter the first textinfo script to read:- 

 

[TextInfo.1]

FrameRate=1,1

WindDirectionAndSpeed=1,6

 

and when you hit shift-Z it will pop up in the rt corner.

 

pj

Do you mean your average wind component for cruise? I know your problem, in the PMDG 737NGX it asks for this value in xxx degrees/xxx kts, but as PFPX only gives the head wind component (i.e. HD056 or TL078 etc.) there's no way to find out the angle. If you don't have the angle of the wind you can't figure out the actual wind speed so there's no way you can enter that in that field if you take the wind from PFPX.

If you mean converting the local wind angle/speed to your headwind component for takeoff, there's one simple way with some maths.

I made this equation for myself that I use in the MD-11, because that aircraft asks for a headwind component for takeoff: H = cos(d) * v. 
H is Headwind, d is difference between actual wind direction and runway heading in degrees, v is the actual wind speed. 

So for example. Wind is 080/15, and I take off from runway 05 which has a runway heading of 050 degrees. d = difference between runway heading and wind direction = 080 - 050 = 030 = 30 degrees. v = wind speed = 15 KTS (given my local METAR). So, H = cos(d) * v = cos(30) * 15 = 12.99 KTS. Just round that up to 13 and voila, there you have your headwind component for take-off, 13 KTS while the actual wind speed is 15 KTS.

Another example: wind is 189/23 and you take-off from runway 24 which has a runway heading of 237. Then d = 237 - 189 = 48 degrees. v = 23 KTS (given by local METAR). Put the values into the equation: H = cos(48) * 23 = 15.39 KTS. Round that up to 16 KTS and put it into the relevant field.

Do you mean your average wind component for cruise? I know your problem, in the PMDG 737NGX it asks for this value in xxx degrees/xxx kts, but as PFPX only gives the head wind component (i.e. HD056 or TL078 etc.) there's no way to find out the angle. If you don't have the angle of the wind you can't figure out the actual wind speed so there's no way you can enter that in that field if you take the wind from PFPX.

 

If you mean converting the local wind angle/speed to your headwind component for takeoff, there's one simple way with some maths.

 

I made this equation for myself that I use in the MD-11, because that aircraft asks for a headwind component for takeoff: H = cos(d) * v.

H is Headwind, d is difference between actual wind direction and runway heading in degrees, v is the actual wind speed.

 

So for example. Wind is 080/15, and I take off from runway 05 which has a runway heading of 050 degrees. d = difference between runway heading and wind direction = 080 - 050 = 030 = 30 degrees. v = wind speed = 15 KTS (given my local METAR). So, H = cos(d) * v = cos(30) * 15 = 12.99 KTS. Just round that up to 13 and voila, there you have your headwind component for take-off, 13 KTS while the actual wind speed is 15 KTS.

 

Another example: wind is 189/23 and you take-off from runway 24 which has a runway heading of 237. Then d = 237 - 189 = 48 degrees. v = 23 KTS (given by local METAR). Put the values into the equation: H = cos(48) * 23 = 15.39 KTS.

Round that up to 16 KTS and put it into the relevant field.

 

 

Do you mean your average wind component for cruise? I know your problem, in the PMDG 737NGX it asks for this value in xxx degrees/xxx kts, but as PFPX only gives the head wind component (i.e. HD056 or TL078 etc.) there's no way to find out the angle. If you don't have the angle of the wind you can't figure out the actual wind speed so there's no way you can enter that in that field if you take the wind from PFPX.

 

If you mean converting the local wind angle/speed to your headwind component for takeoff, there's one simple way with some maths.

 

I made this equation for myself that I use in the MD-11, because that aircraft asks for a headwind component for takeoff: H = cos(d) * v.

H is Headwind, d is difference between actual wind direction and runway heading in degrees, v is the actual wind speed.

 

So for example. Wind is 080/15, and I take off from runway 05 which has a runway heading of 050 degrees. d = difference between runway heading and wind direction = 080 - 050 = 030 = 30 degrees. v = wind speed = 15 KTS (given my local METAR). So, H = cos(d) * v = cos(30) * 15 = 12.99 KTS. Just round that up to 13 and voila, there you have your headwind component for take-off, 13 KTS while the actual wind speed is 15 KTS.

 

Another example: wind is 189/23 and you take-off from d = 237 - 189 = 48 degrees. v = 23 KTS (given by local METAR). Put the values into the equation: H = cos(48) * 23 = 15.39 KTS.

Round that up to 16 KTS and put it into the relevant field.

In the FMC (takeoff page) there is a feild of : slope/H wind.

The runway slope not modeled by flighsim, so we need set ZERO.

But in the H wind, yes its the HEAD WIND COMPONENT

So i will use ur equation to know the H to put it in the H wind.

But small quistion, in the two examples how u get the 080/15 & 189/23 values ?

In the FMC (takeoff page) there is a feild of : slope/H wind.

The runway slope not modeled by flighsim, so we need set ZERO.

But in the H wind, yes its the HEAD WIND COMPONENT

So i will use ur equation to know the H to put it in the H wind.

But small quistion, in the two examples how u get the 080/15 & 189/23 values ?

I actually better know what aircraft you're flying in this situation. In some you don't have to use the equation at all, and you can simply enter the actual wind direction/speed and the FMC will automatically convert that to a headwind component. The PMDG 737NGX and 777 do just that, and you can simply enter the actual wind direction/speed in the RW WIND field which is above the RW SLOPE field. But the PMDG MD-11 does not, it asks for a headwind component which can be calculated manually by using my equation filling in values like wind direction relative to runway and the actual wind speed. 

 

Now to answer your question, the numbers I gave (i.e. 080/15) were just random examples of wind direction/speed values at a random airport. You can find the wind direction/speed of your local airport in several ways. Firstly, you can press SHIFT+Z and your wind should be displayed somewhere in that red lettered line. Secondly, you can simply get it from the METAR of the applicable airport. Flightplanners like PFPX give the METAR for you departure and arrival airport under the Weather tab. Beware though, it is written in a particular "aviation language". Here's little sample of a METAR (the whole thing is much longer and also gives info about cloud coverage etc.):

 

METAR EHAM 030125 21044G54: The weather at EHAM at the 3rd of November at 0125 zulu is: 210 degrees at 44 KTS with gusts to 54 KTS. 

 

That's how you get your wind direction and wind speed. :smile: If it's possible, simply enter the value directly into the FMC, and the FMC will convert that to a headwind component. So in case of EHAM you would enter 210/44. If you can't do that, like in the MD-11 just use the equation. I.e., you take off from runway 24 with a heading of 238. d = 238 - 210 = 28 degrees. v = 44 KTS (given by metar). Headwind Component = cos(28) * 44 = ...  

 

That's it!