HiI am trying to accomplish that the element shouldn't be show when the variable is either 0 or 4 I tried the following but it doesn't work dont know why if I take away one of the conditions it works?BrgdsEugen(L:Cursor_post, enum) 0 != (L:Cursor_post, enum) 4 != ||(**** Position 1 *****)(L:Cursor1, number) 10 !=%((L:Cursor1, number))%!1d!

Eugen,Did you try:(L:Cursor_post, enum) 0 > (L:Cursor_post,enum) 4 < &&Jan"Beatus Ille Procul Negotiis"

Hi Eugen,The code could of course not work. In your visible code you wrote that the value is visible if either the enum is not 0 or not 4. Because of this you could set the number as you like and it will ALWAYS be visible. For example or better understanding:In your code if your number is 0 it is visible because your code says OR "not enum 4" If the the number is = 0 it is of course not number = 4 and that's why it is still visible.It's necessary to rework your visibility code. You have two possibilities here:(L:Cursor_post, enum) 1 == (L:Cursor_post,enum) 2 == (L:Cursor_post, enum) 3 == || ||or use an "AND" instead of the "Or" command:(L:Cursor_post, enum) 0 != (L:Cursor_post,enum) 4 != &&Hope this helps.Best RegardsMatthias

Thanks guys, worked it out this morning :-)BrgdEugen