Hi,Does anyone know of a neat way to find the lowest in a group of variables?I.E I have 5 variables with different values and I need to pick the lowest value at any given time.Any ideas?

Hi Paul,This is what first came in mind: (maybe not the most efficient:-))(L:Var1,number) (>L:VarMin,number) (L:Var2,number) d (L:VarMin,number) < if{ (>L:VarMin,number) }(L:Var3,number) d (L:VarMin,number) < if{ (>L:VarMin,number) }(L:Var4,number) d (L:VarMin,number) < if{ (>L:VarMin,number) }(L:Var5,number) d (L:VarMin,number) < if{ (>L:VarMin,number) }Use (L:VarMin,number) as referenceHope this helpsTom

Tom,Much more efficient than the route my brain was going!Many thanks,

Hi Paul,Glad it was useful! If you need to handle Var1..Var5 independent from VarMin within a gauge, you can use a macro:(L:Var1,number) s0(L:Var2,number) d l0 < if{ s0 }(L:Var3,number) d l0 < if{ s0 }(L:Var4,number) d l0 < if{ s0 }(L:Var5,number) d l0 < if{ s0 }l0And then check the VarMin Value ie:..@VarMin 10 < if{ XXX } etcCheersTom

Euhh....What's wrong with:var1 var2 var3 var4 var5 min min min min :-) ??Cheers, Rob Barendregt.

"What's wrong with:var1 var2 var3 var4 var5 min min min min :-) ??"I can't see anything. Should be something??:-lol:-lol:-lolCheersTom

Ok thanks... Sorry for being thick but what does min do?

Paul,min takes the smallest of two values. ie "10 12 min" returns 10.What Rob showed seems to be the most efficient way I was talking about :-)Regards,Tom

Excellent thanks,

Q.E.D. :-)Cheers, Rob