Here's a short C routine that will (eventually) print a googolplex, that is 10^googol power.A googol, for those who may not remember is simply 10^100 power, or 1 followed by 100 zeros.Now, given today's processor speeds, how long would it take to complete printing? :)#include #include int main (int argc, char *argv[]){ int *vals, *ptr, max; if (argc == 2) max = atoi (argv[1]); else max = 100; printf ("1"); if ((vals = malloc ((max + 1) * sizeof (int))) == NULL) { fprintf (stderr, "Error allocating memory.n"); return 1; } memset (vals, '0', (max + 1) * sizeof (int)); while (!vals[max]) { *(ptr = vals) += 1; while (*ptr == 10) { *ptr++ = 0; *ptr += 1; } printf ("0"); } printf ("n"); free (vals); return 0;}http://fpx.de/fp/Fun/Googolplex/

Dunno. How long?-Dai !

The fastest available desktop computers of today will run the program at a speed that allows the printing of about 10 to the power of 7 digits per second. The average year has roughly 3.2*10^7 seconds, so this machine will print about 3.2*10^14 digits per year. We conclude that this machine will need 3.125*10^85 years to finish printing Googolplex. Lucas Watson ([email protected]) took a different approach, and pointed out that this program will be useless even in a million years, simply because there isn't enough matter (in the universe) to print a Googolplex on (and this fact is unlikely to change). According to him, this idea originated on Carl Sagan's Cosmos TV show. Of course printing a Googolplex in base Googolplex is easy:If we switch to base Googolplex, you can print it simply as 10