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Question for CPL pilots ;)

Featured Replies

Heys guys,

I have come up with few questions 

 

Q.1 Temperature at 2KM is 5*C what is ISA deviation ? Hint(Actual - ISA) Given that temperature falls 6.5*C/1KM while going up.

 

Q.2 In actual atmosphere temp at 19KM is -60*C. Find ISA Deviation?Given that temperature falls 6.5*C/1KM while going up.

 

Also give reasons/proof for your answerers.. 

BTW these are real type Exam questions for CPL

1y329d.jpg

I don't have a CPL, so waiting for a real CPL to answer, I'll give mine:

 

Q.1 ISA SL temperature is 15C. In this case, temperature at SL will be: 5 + (6.5 x 2) = 18C, so that makes: 18-15 = +3C ISA deviation.

 

Q.2 I don't know if this is the correct answer, maybe not. However, ISA atmosphere has constant temperature above 11km. So, in this case you'll have -60C at 11km, and -60 + (6.5 x 11) = 11.5C at SL, so that makes: 11.5-15 = -3.5C ISA deviation.

"Society has become so fake that the truth actually bothers people".

I thought it fell around 2º per 1000 feet... Unless the exam is using some funny values (like km!)

Brendan R, KDXR PHNL KJFK

Type rated: SF34 / DH8 (Q400) / DC9 717 MD-88/ B767 (CFI/II/MEI/ATP)

Majestic Software Q400 Beta Team / Pilot Consultant / Twitter @violinvelocity

Feet are the funny values in this case, By definition in the temperature fall by 6.5OC/km (0.0065OC/m) below 11km

Gerry Howard

  • Author

I thought it fell around 2º per 1000 feet... Unless the exam is using some funny values (like km!)

2*C/1000 feet = 3.5*F/1000 feet = 6.5*C/KM

1y329d.jpg

  • Author

I don't have a CPL, so waiting for a real CPL to answer, I'll give mine:

 

Q.1 ISA SL temperature is 15C. In this case, temperature at SL will be: 5 + (6.5 x 2) = 18C, so that makes: 18-15 = +3C ISA deviation.

 

Q.2 I don't know if this is the correct answer, maybe not. However, ISA atmosphere has constant temperature above 11km. So, in this case you'll have -60C at 11km, and -60 + (6.5 x 11) = 11.5C at SL, so that makes: 11.5-15 = -3.5C ISA deviation.

I think that is right too but check my method

Ans.1) The formula for Finding ISA Deviation is = Actual Temperature - ISA Temp.

We know the Actual temperature that is 5*C but we don't know the ISA temp.

 

We also know that

ISA at Sea level is +15*C with increase in altitude temp reduces at rate of 6.5*C/1km 

 

So ISA Temp for 2 km will be 15-6.5*2=15-13 ... = 2*C

 

So now I know the ISA temprature I will simply use ISA dev formula = Actual Temp(Given 5*C) - ISA temp(2*C)= 3*C 

1y329d.jpg

Yes, the two methods are absolutely equivalent.

"Society has become so fake that the truth actually bothers people".

2*C/1000 feet = 3.5*F/1000 feet = 6.5*C/KM

 

OF are irrelevant here and, anyway, 2OC = 3.6OF - not 3.5OF

There are 3.28083 feet / metre so the relationship is simply

6.5OC / 1000m = (6.5 / 3.28083) OC / 1000ft = 1.9812OC / 1000ft.

Gerry Howard

Ah ok. I just look at the FMC these days...

Brendan R, KDXR PHNL KJFK

Type rated: SF34 / DH8 (Q400) / DC9 717 MD-88/ B767 (CFI/II/MEI/ATP)

Majestic Software Q400 Beta Team / Pilot Consultant / Twitter @violinvelocity

  • Author

OF are irrelevant here and, anyway, 2OC = 3.6OF - not 3.5OF

There are 3.28083 feet / metre so the relationship is simply

6.5OC / 1000m = (6.5 / 3.28083) OC / 1000ft = 1.9812OC / 1000ft.

We take the approx value in all these case so to make calculations easier. On some books you will read value a change by few points so it's considered the same.

 

Example on some books you will see percentage of Carbon dioxide to be 0.03% and on some 0.05%. It varies but since it is in a very small amount it is considered the same

1y329d.jpg

I agree the approximations are acceptable for day-to-day use but 2OC does not equal 3.5OF as you wrote.

Gerry Howard

After getting my ATP I've used 0 of the equations required. Through theory of flight I used to be able to calculate nearly everything by memory but once you start flying the only thing we care about is if we are starting our descent so it is a nice stable 1500 fpm descent. 

Chris Miller

  • Author

After getting my ATP I've used 0 of the equations required. Through theory of flight I used to be able to calculate nearly everything by memory but once you start flying the only thing we care about is if we are starting our descent so it is a nice stable 1500 fpm descent. 

That is right but DGCA and JAA are different from FAA .However they are co-related (ofcourse) but much more complex and detailed

1y329d.jpg

That is right but DGCA and JAA are different from FAA .However they are co-related (ofcourse) but much more complex and detailed

I know the FAA tests are a joke, but Theory of Flight classes are no joke. We would take a whole 4 hour class session working in minutia just to find how a rotation or stall speed would be changed.

Chris Miller

I'm always impressed by how much knowledge the JAA tests required. It basically is a degree's worth of stuff! The tests are hard, no joke, and require diligent study.

 

That being said, you'll use 1% of it actually flying! 

Brendan R, KDXR PHNL KJFK

Type rated: SF34 / DH8 (Q400) / DC9 717 MD-88/ B767 (CFI/II/MEI/ATP)

Majestic Software Q400 Beta Team / Pilot Consultant / Twitter @violinvelocity

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